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y^2-22y-135=0
a = 1; b = -22; c = -135;
Δ = b2-4ac
Δ = -222-4·1·(-135)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-32}{2*1}=\frac{-10}{2} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+32}{2*1}=\frac{54}{2} =27 $
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